I forgot how to solve y^2(5-2y), to.give my answer in surd form. I thought to use -b+/-sqrt(b^2-4ac)/2a but I got an imaginary number and I don't think I can use completing the square method either..please help thanks a lot!

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- Nov 22nd 2012, 04:33 PMTutusimple algebra
I forgot how to solve y^2(5-2y), to.give my answer in surd form. I thought to use -b+/-sqrt(b^2-4ac)/2a but I got an imaginary number and I don't think I can use completing the square method either..please help thanks a lot!

- Nov 22nd 2012, 04:57 PMtopsquarkRe: simple algebra
What do you mean by "solved?" $\displaystyle y^2(5 - 2y)$ is not an equation.

Taking a leap of faith I'm going to assume that you mean to solve

$\displaystyle y^2(5 - 2y) = 0$

In this case we know that $\displaystyle y^2 = 0$ or $\displaystyle 5 - 2y = 0$

Now go from there.

-Dan - Nov 22nd 2012, 08:41 PMTutuRe: simple algebra
Sorry for the not being detailed, the question asked to solve for the value of y. Sorry and thanks!

- Nov 23rd 2012, 03:02 PMtopsquarkRe: simple algebra