# simple algebra

• Nov 22nd 2012, 04:33 PM
Tutu
simple algebra
I forgot how to solve y^2(5-2y), to.give my answer in surd form. I thought to use -b+/-sqrt(b^2-4ac)/2a but I got an imaginary number and I don't think I can use completing the square method either..please help thanks a lot!
• Nov 22nd 2012, 04:57 PM
topsquark
Re: simple algebra
Quote:

Originally Posted by Tutu
I forgot how to solve y^2(5-2y), to.give my answer in surd form. I thought to use -b+/-sqrt(b^2-4ac)/2a but I got an imaginary number and I don't think I can use completing the square method either..please help thanks a lot!

What do you mean by "solved?" $y^2(5 - 2y)$ is not an equation.

Taking a leap of faith I'm going to assume that you mean to solve
$y^2(5 - 2y) = 0$

In this case we know that $y^2 = 0$ or $5 - 2y = 0$

Now go from there.

-Dan
• Nov 22nd 2012, 08:41 PM
Tutu
Re: simple algebra
Sorry for the not being detailed, the question asked to solve for the value of y. Sorry and thanks!
• Nov 23rd 2012, 03:02 PM
topsquark
Re: simple algebra
Quote:

Originally Posted by Tutu
Sorry for the not being detailed, the question asked to solve for the value of y. Sorry and thanks!

It happens. In the future make sure to write down the whole problem. :)

Do you have any questions about my previous post?

-Dan