Hello All,

Having trouble with below question:

The graph of:

$\displaystyle f(x) = x^3+3x^2-x+4$

is translated to its image g(x) by the vector $\displaystyle \binom{-1}{3}$

Write the new equation of g(x) in the form :

$\displaystyle ax^3+bx^2+cx+d$

Ive tried using the GDC to graph f(x) and then translating points by the vector, but was wondering if there is an algebraic way of doing it without using the GDC? Thanks appreciate it.