1. ## Sum of 3^r

How would I find the sum of 3^r from r=1 to r=n?

I honestly have no workings because I don't know how to approach this since I can't split it into 3*(sum[1^r])

2. ## Re: Sum of 3^r

Originally Posted by Mukilab
How would I find the sum of 3^r from r=1 to r=n?

$\displaystyle \sum\limits_{k = 1}^n {t^k } = \frac{{t - t^{n + 1} }}{{1 - t}}$

3. ## Re: Sum of 3^r

Originally Posted by Mukilab
How would I find the sum of 3^r from r=1 to r=n?

I honestly have no workings because I don't know how to approach this since I can't split it into 3*(sum[1^r])
It's a geometric series with \displaystyle \displaystyle \begin{align*} a = 3 \end{align*} and common ratio \displaystyle \displaystyle \begin{align*} \rho = 3 \end{align*}.
The sum of a finite geometric series can be evaluated using \displaystyle \displaystyle \begin{align*} S_n = \frac{a \left( 1 - \rho ^n \right)}{1 - \rho} \end{align*}.