Hello

The question is, solve:

$\displaystyle 2\log_{x}4 - \log_{2}x = 3 $

Changing the base I get:

$\displaystyle \log_{x}16 - \dfrac{\log_{x}x}{\log_{x}2} = 3 $

$\displaystyle \log_{x}16 - \dfrac{1}{\log_{x}2} = 3 $

I don't know how to proceed from here.

I know that the difference between two logs with the same base can be written as a division, but the reciprocal is throwing me off.

I would greatly appreciate some help.

Thank you.