Let f(x,y) = (-2y)(-2x) - [1 - 2x - 2y]^2, then
f(0,1) = (-2*1)(-2*0) - [1 - 2*0 - 2(1)]^2 = (-2)(0) - [1 - 0 - 2]^2 = 0 - [-1]^2 = -1
so I have this
-2 - [1 - 2]^2
the answer is -1
this is where i get confused... i know that 1 - 2 is -1, square that -1^2 is positive 1 so it's going to look like this.... -2 - 1.... why am i getting -3 when the correct answer is -1....
the original equation is this, (-2y)(-2x) - [1 - 2x - 2y]^2...... where you plug in values of x and y...... x=0 and y=1