1) Evaluate: log_{6}6√6

I thought that by the power of a power law, I can make the logarithm:

= log_{6}(6)(6)^{0.5}

= 0.5 log_{6}(6)(6)

= 0.5 log_{6}(36)

= 0.5 log_{6}(6)^{2}

= (2)(0.5) log_{6}6

= 1

However, the answer is 1.5 and I'm not sure where I went wrong; any corrections/hints?

2) Write each expression as a single logarithm; assume that all the variables represent positive numbers

1 + log_{3}x^{2 }I really don't know what to do with this one, and the answer is log_{3}3x^{2}.

Please and thank you!