Add the Radicals: sqrt48 + sqrt27
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Originally Posted by flippin4u Add the Radicals: sqrt48 + sqrt27 Hi, you can partially calculate the square-root: $\displaystyle \sqrt{48}+\sqrt{27}=\sqrt{16 \cdot 3} + \sqrt{9 \cdot 3} = \sqrt{16} \cdot \sqrt{3}+\sqrt{9}\cdot \sqrt{3}= 4 \cdot \sqrt{3}+3 \cdot \sqrt{3}=7 \cdot \sqrt{3}$
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