How to solve for x? Exponent rules?

x^-1/4 = 2

Any suggestions/hints? Please and thank you!

Note that (x^a)^b = x^ab and that -1/4 * -4 = 1.

Can you finish?

I got it - x = (1/16)! Thank you so much! :)

Quote:

---

Originally Posted by misiaizeska

x^-1/4 = 2
Any suggestions/hints? Please and thank you!

---

Another way is: 1 / x^(1/4) = 2 : x^(1/4) = 1/2

X^-1/4 =2
-1/4 log base 2 (x) =log base2 (2) =1
log base 2 (X) =-4
X=1/16