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Math Help - Simplify this function

  1. #1
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    Simplify this function

    I have an equation that looks like this
    v=v_0 sqrt(1-2gt sin\theta /v_0+(gt/v_0)^2)

    Is there any easy way to simplify this? It's almost a perfect square.
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  2. #2
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    Re: Simplify this function

    Well, you can put the quantity under the square root under common denominator v0 so that you will cancel the v0 at the outside and will get [v02-2gtv0sinx+(gt)2]1/2
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  3. #3
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    Re: Simplify this function

    Quote Originally Posted by jeremy5561 View Post
    I have an equation that looks like this
    v=v_0 sqrt(1-2gt sin\theta /v_0+(gt/v_0)^2)

    Is there any easy way to simplify this? It's almost a perfect square.
    have to ask ... is there more to this than meets the eye? in other words, how did this equation come about?
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  4. #4
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    Re: Simplify this function

    For a projectile launched with velocity v_0 at angle \theta, what is the magnitude of the velocity vector at time t?

    v_0_x=v_0cos\theta t
    v_0_y=v_0sin\theta t-gt

    Apply the pythagorean theorem and you'll end up where I am.

    Unless I did something wrong. Stayed up till 2 AM doing this stuff.
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  5. #5
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    Re: Simplify this function

    fix your equations ...

    v_x = v_0 \cos{\theta}

    (note there is no t ... velocity in the x-direction remains constant)


    v_y = v_0 \sin{\theta} - gt

    (first term does not have a t)
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  6. #6
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    Re: Simplify this function

    sorry, am really tired. I did it correctly originally. Don't think it can be simplified further.
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