# solving for x with multiple exponents higher than 2

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• Nov 11th 2012, 05:25 PM
kingsolomonsgrave
solving for x with multiple exponents higher than 2
Attachment 25657

I don't understand what is going on in the pink area. Can someone explain this?

thanks
• Nov 11th 2012, 06:13 PM
skeeter
Re: solving for x with multiple exponents higher than 2
it's just factoring ...

$8(x+3)^7 (x-5)^4 + 4(x+3)^8(x-5)^3 = 0$

note the two terms have $4(x+3)^7$ and $(x-5)^3$ in common. factor them out ...

$4(x+3)^7(x-5)^3[2(x-5) + (x+3)] = 0$
• Nov 11th 2012, 06:21 PM
kingsolomonsgrave
Re: solving for x with multiple exponents higher than 2
oh I see now. ok thanks!