1. ## fractions URGENT!!!

guys im stuck on these 2 Q's and its due in for tomorow plz can some1 explain it properly:
charlie cycles 5 and 5 over 8( a fraction) miles in three quatres of an hour.
a. at what speed does he cycle in miles per hour?
b. at the same speed,how far would he cycle in 5o minutes?

the outside measurements of a picture frame are 12 and one tenths( 1 over 10)cms and 6 and 3 over 4 cm.the frame is 1 over 2 cm wide.
what is the area of the picture?
thankyou

2. Originally Posted by help_me
guys im stuck on this Q plz can some1 explain it properly:
charlie cycles 5 and 5 over 8( a fraction) miles in three quatres of an hour.
a. at what speed does he cycle in miles per hour?
recall that $\mbox{Speed }= \frac {\mbox{Distance}}{\mbox{Time}}$

I change $5 \frac 58$ to $\frac {45}8$

So he cycles $\frac { \left( \frac {45}8 \right) \mbox { miles}}{ \left( \frac 34 \right) \mbox { hour}} = \frac {\frac {45}8}{ \frac 34}$ mph

can you solve that?

b. at the same speed,how far would he cycle in 5o minutes?
after you find the speed from part (a), use the fact that $\mbox { Distance} = \mbox {Speed} \times \mbox {Time}$ and plug in the speed and time to solve for distance

here, put the time as $\frac 56$ hours

3. Originally Posted by help_me
the outside measurements of a picture frame are 12 and one tenths( 1 over 10)cs and 6 and 3 over 4 cm.the frame is 1 over 2 cm wide.
what is the area of the picture?
thakyou
you need to learn how to type fractions better.

i suppose you mean the outside measurements of the frame are $12 \frac 1{10}$ cm by $6 \frac 34$ cm. and the frame is 1/2 cm thick (that is, its border around the picture is 1/2 cm)

Now $12 \frac 1{10} = \frac {121}{10}$

and $6 \frac 34 = \frac {27}4$

so the length of the picture will be $\left( \frac {121}{10} - 1 \right)$ cm. (since we subtract 1/2 cm at the top and bottom for the picture frame)

and the width of the picture is $\left( \frac {27}4 - 1 \right)$ cm (since we subtract 1/2 cm from both sides for the picture frame)

So the area of the picture is: $\mbox{length} \times \mbox{width} =\left( \frac {121}{10} - 1 \right) \left( \frac {27}4 - 1 \right)$

can you take it from here? work out what are in the brackets first

4. ## hmm...

would the anwser to a. be 7 and 1 over 2?
would b. be 6 and 1 over 4?
hey how did u work out da time to be 5 over 6?sorry i didnt understand...........

5. ## ummm

would da second q's anwser be 63 and 33/40?

6. Originally Posted by help_me
would the anwser to a. be 7 and 1 over 2?
yes

would b. be 6 and 1 over 4?
yes

hey how did u work out da time to be 5 over 6?sorry i didnt understand...........
i needed to know what fraction of an hour is 50 minutes. now i know that 1 hour = 60 minutes. so (1/60)hour = 1 minute. multiply both sides by 50, we get: (50/60)hour = 50 minutes

Originally Posted by help_me
would da second q's anwser be 63 and 33/40?
yes. (with cm^2 as the units)

7. ## thanks sooo much

ure a life saver!