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Math Help - Algerbra Help Needed Fast

  1. #1
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    Algerbra Help Needed Fast

    Anyone got a clue?

    x^2+3x-4y+5=2
    6=x-2y


    thanks
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  2. #2
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    Re: Algerbra Help Needed Fast

    Substitute x = 2y+6 into the first equation. Solve for y. Then substitute y into either equation (preferably the second) to find x.
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  3. #3
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    Re: Algerbra Help Needed Fast

    Can you work the whole thing out? i'm clueless about maths.
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  4. #4
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    Re: Algerbra Help Needed Fast

    Generally, I don't post entire solutions as this is a homework help forum. I can't just do the whole problem for you, you won't learn as much. I'll help you get started:

    We substitute x = 2y+6 into the first equation:
    (2y+6)^2 + 3(2y+6) - 4y + 5 = 2.

    Expand:
    (4y^2 + 24y + 36) + (6y + 18) - 4y + 5 = 2

    You should be able to simplify the above expression into a quadratic in terms of y. Hopefully you know how to solve quadratics. If you don't, you should review that before continuing on with the problem.
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