Find each function value.g(x)=x^{3}-2x

(a) g(3)= 1 (b) g(10)= 2 (c) g(-3)= 3 (d) g(7)= 4

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- Nov 5th 2012, 10:16 AM #1

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- Nov 5th 2012, 10:24 AM #2
## Re: Can anyone help?

To find value of a function at x=a, where a is some constant, you replace every x in that function with a.

$\displaystyle g(x)=x^3-2x$

(a) $\displaystyle g(3)=3^3-2*3=27-6=21.$

(b) $\displaystyle g(10)=10^3-2*10=1000-20=980$.

So your answers are incorrect, but I hope you understand now, can you do rest of the problem (parts (c) and (d))?

- Nov 5th 2012, 10:28 AM #3

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- Nov 5th 2012, 10:38 AM #4

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- Nov 5th 2012, 12:30 PM #5