# Can anyone help?

• Nov 5th 2012, 10:16 AM
impressu2
Can anyone help?
Find each function value.g(x)=x3-2x

 (a) g(3) = 1 (b) g(10) = 2 (c) g(-3) = 3 (d) g(7) = 4
• Nov 5th 2012, 10:24 AM
Re: Can anyone help?
Quote:

Originally Posted by impressu2
Find each function value.g(x)=x3-2x

 (a) g(3) = 1 (b) g(10) = 2 (c) g(-3) = 3 (d) g(7) = 4

To find value of a function at x=a, where a is some constant, you replace every x in that function with a.

$g(x)=x^3-2x$

(a) $g(3)=3^3-2*3=27-6=21.$

(b) $g(10)=10^3-2*10=1000-20=980$.

So your answers are incorrect, but I hope you understand now, can you do rest of the problem (parts (c) and (d))?
• Nov 5th 2012, 10:28 AM
Petrus
Re: Can anyone help?
he had exact same question early and why do he give the answer "1,2,3,4" plz i hope you dont try that you want us to solve ur homework...
• Nov 5th 2012, 10:38 AM
impressu2
Re: Can anyone help?
it's not the same question, and I not looking for answers only, I am trying to really understand it. As for the 1234 numbers, I am not putting those, I think it's a pc error.
• Nov 5th 2012, 12:30 PM
skeeter
Re: Can anyone help?
you've been given ample instruction in evaluating function values. thread closed.