Linear Equation: 7x+5/3=11 Answer: x=4/3 ... I'm not getting that answer and don't know in which step I went wrong.
Can someone expand and this and show me how the solution was derived. Thank you!
I'm struggling with 9th grade math :-(
But here's how I did it: 3+5*7x/3=11
3+35x/3=11
3+35x=3*11
3+35x=33
-3 3+35x=33 -3
35x = 30
x = 35/30...
I don't understand the sequence of numbers you have to either add or multiply when solving the equation. How do I know what to multiply with such equations?
the misstake u do is that u cant multiplicate 7x with 5 :P your method seems like a tutor its simple look at his tips!
dw i also sometimes struggle with 9th grade mat
if the equation is
$\displaystyle \frac{7x+5}{3} = 11$
then that x=4/3 is wrong answer
if we multiplicate with 3 then we get
$\displaystyle \frac{7x+5}{1} = 33$ (why i got divide by 1 is because im not good with that latex code.. it get strange if i take away 1 but you understand)
can you finish this?
next time use grouping symbols to make your equation clear to those who read it ...
$\displaystyle \frac{7x+5}{3} = 11$Linear Equation: (7x+5)/3=11
multiply both sides by 3 to clear the fraction ...
$\displaystyle 7x+5 = 33$
subtract 5 from both sides ...
$\displaystyle 7x = 28$
divide both sides by 7 ...
$\displaystyle x = 4$
substitute your solution back into the original equation to check ...
$\displaystyle \frac{7(4)+5}{3} = \frac{28+5}{3} = \frac{33}{3} = 11$