Solving for Exponents as Variables

**sakonpure6** · November 4th 2012, 02:06 PM

I have the equation $Value = 6(0.92)^n$
I need to know what the cost will be when the Value is 1

So I did this

$Value = 6(0.92)^n$
$1 = 6(0.92)^n$
$1/6 = 0.92^n$

I'm stuck there. Any help is appreciated!

**topsquark** · November 4th 2012, 02:10 PM

Originally Posted by sakonpure6

I have the equation $Value = 6(0.92)^n$
I need to know what the cost will be when the Value is 1

So I did this

$Value = 6(0.92)^n$
$1 = 6(0.92)^n$
$1/6 = 0.92^n$

I'm stuck there. Any help is appreciated!

Hint: $\log_{10} \left ( 0.92 ^n \right )$ is what?

(or you could use ln just as easily.)

-Dan

**sakonpure6** · November 4th 2012, 02:14 PM

Originally Posted by topsquark

Hint: $\log_{10} \left ( 0.92 ^n \right )$ is what?

(or you could use ln just as easily.)

-Dan

Lol, I'm sorry but I have no Idea what log and In are or how to solve that!

**skeeter** · November 4th 2012, 02:19 PM

Originally Posted by sakonpure6

Lol, I'm sorry but I have no Idea what log and In are or how to solve that!

then you need to learn how ...

Solving Exponential Equations by Using Logarithms

**sakonpure6** · November 4th 2012, 02:20 PM

Originally Posted by skeeter

then you need to learn how ...

Solving Exponential Equations by Using Logarithms

great! Much appreciated!

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