$\displaystyle -(x-2)(x^2+2x+5)$

$\displaystyle -(x^3+2x^2+5x-2x^2+4x-10)$

$\displaystyle -(x^3+x-10)$

$\displaystyle -x^3-x+10$

How do you factor this? I tried adding in a $\displaystyle 0x^2$ and grouping, but that didn't work out. The other group can't factor out to $\displaystyle x-0$...