how to set 2x^{2}-4x-1 eqaul to 0? do you have to factor it first or does it matter?
$\displaystyle b^2-4ac$ is not a perfect square, so the expression will not factor over the rationals ... you'll have to complete the square or use the quadratic formula.
do i need the whole quadratic formula or the just b^2-4ac part you mentioned?
Originally Posted by skeeter
$\displaystyle b^2-4ac$ is not a perfect square, so the expression will not factor over the rationals ... you'll have to complete the square or use the quadratic formula.