Assuming you mean e^(Lx), yes. The

**definition** of the (natural) logarithm is that it is the inverse function to e^x: log(e^x)= x. So if you take the logarithm of both sides, log(y+ 1)= log(e^(Lx))= Lx. Now divide both sides by L.

vi) y=xcos^2 + xsin^2

Completely stumped

So am I! I have no idea what "cos" and "sin", could possibly mean without an argument! Is it possible you meant cos^2(x)+ sin^2(x) or xsin^2(x)+ xcos^2(x)? If it is either of those, use the fact that sin^2(x)+ cos^2(x)= 1.

vii) y=log(e^x)

Not sure where to begin

All help is apprecaited! many thanks