How would I factor 2(x^2 + y^2) to this x^2 + 2xy + y^2 + x^2 - 2xy + y^2. I know they are equal but I don't see a path to get there.
Thanks for any suggestions.
Hello nicnicman.
$\displaystyle 2(x^2+y^2)=(x^2+y^2)+(x^2+y^2)$, which is the same as $\displaystyle x^2+2xy+y^2+x^2-2xy+y^2$ because 2xy and -2xy cancel each other. I hope you understand.
Last edited by PaulAdrienMauriceDirac; Oct 31st 2012 at 03:12 AM.