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Math Help - Need help with an equation!

  1. #1
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    Need help with an equation!

    Hello Everyone, I need help with the following equation:

    1/2m + 1 = 5/6m -2

    Cheers Valkyriel

    Edit:

    Need help with another one aswell

    3/x-1 = 5/2x+1
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: Need help with an equation!

    Please use bracketing symbols to make it clear what the denominators are. You may know what you mean, but there is doubt, at least to me, what the intended equations are.
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  3. #3
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    Re: Need help with an equation!

    My bad, never really did math on computers.

    First one:


    Second one:
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  4. #4
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    Re: Need help with an equation!

    A start to both:

    (m + 1) / 2 = (5m - 10) / 6

    3(2x + 1) = 5(x - 1)

    If you're unable to continue, you need classroom help...
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  5. #5
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    Re: Need help with an equation!

    I still don't get it...
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    Re: Need help with an equation!

    Quote Originally Posted by Wilmer View Post
    If you're unable to continue, you need classroom help...
    Does that mean you won't help me further?
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    Re: Need help with an equation!

    Quote Originally Posted by Wilmer View Post
    if you're unable to continue, you need classroom help...
    Hey thats not nice to say!
    ehmm u can look step by step soulotion if u dont understand :P
    1/2m + 1 = 5/6m -2 - Wolfram|Alpha
    3/(x-1) = 5/(2x+1) - Wolfram|Alpha
    i think u need to register to see it but its worth it hope it help!
    Last edited by Petrus; October 30th 2012 at 12:22 PM.
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  8. #8
    Junior Member alane1994's Avatar
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    Re: Need help with an equation!

    I assume that you are solving for "m"?

    Original Problem:
    \frac{1}{2}m+1=\frac{5}{6}m-2

    Multiply and get and get common denominator.

    \frac{m+2}{2}=\frac{5m+12}{6}

    Can you continue from here?

    Also if you use wolfram, be sure to use parentheses.
    First one on wolfram
    (1/2)m + 1 = (5/6)m -2 - Wolfram|Alpha
    Thanks from Petrus and Valkyriel
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  9. #9
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    Re: Need help with an equation!

    sorry i did confuse with x and m
    this maybe against the forum rule but ima show u step by step how to solve one of them ( the x one)
    u got
    3/(x-1)=5/(2x+1)
    with a law u can swap idk the name so u got
    3(2x+1)=5(x-1)
    now lets multiplice the parentes so we got
    6x+3=5x-5
    now we subtra with 5 (u take -5 on both side) and we got
    x+3=-5
    u want x alone so u have to get away with 3 so we do -3 both side then u got
    x=-8
    Now u have solved this problem! cheer =D hope u did understand and gl on the other problem
    Thanks from Valkyriel
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    Re: Need help with an equation!

    Thanks to both of you
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  11. #11
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    Re: Need help with an equation!

    Quote Originally Posted by Petrus View Post
    x=-8
    Now u have solved this problem!
    Petrus, please use YOU, not U. Can be confusing, if u is a variable.

    He has NOT solved it: you have!
    How do you think that'll help him? His teacher will think he did it by himself...
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    Re: Need help with an equation!

    Quote Originally Posted by Wilmer View Post
    Petrus, please use YOU, not U. Can be confusing, if u is a variable.

    He has NOT solved it: you have!
    How do you think that'll help him? His teacher will think he did it by himself...
    sorry im used to use "u". Sometimes you learn to see how to solve especially this is not "hard". I learned alot from see how to solve and thats what i sometimes i do. Sorry i did solve 1 and let him solve the 2
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  13. #13
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    Re: Need help with an equation!

    My only point is we're not here to do homework...
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  14. #14
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    Re: Need help with an equation!

    Quote Originally Posted by Wilmer View Post
    My only point is we're not here to do homework...
    I totaly agree with u but we all know that homework is not a "big deal" for the grade. He will need to show all his skill in test so w/e done is done.. he maybe learned something now
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  15. #15
    Junior Member alane1994's Avatar
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    Re: Need help with an equation!

    Homework is a big deal. It is worth 30% on my grade in calculus. Try again. And we are not here to do others homework, but rather help.
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