Hello Everyone, I need help with the following equation:

1/2m + 1 = 5/6m -2

Cheers Valkyriel

Edit:

Need help with another one aswell

3/x-1 = 5/2x+1

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- Oct 30th 2012, 08:42 AMValkyrielNeed help with an equation!
Hello Everyone, I need help with the following equation:

1/2m + 1 = 5/6m -2

Cheers Valkyriel

Edit:

Need help with another one aswell

3/x-1 = 5/2x+1 - Oct 30th 2012, 09:11 AMMarkFLRe: Need help with an equation!
Please use bracketing symbols to make it clear what the denominators are. You may know what you mean, but there is doubt, at least to me, what the intended equations are.

- Oct 30th 2012, 09:40 AMValkyrielRe: Need help with an equation!
My bad, never really did math on computers.

First one:

http://i.imgur.com/NmT5T.png

Second one:

http://i.imgur.com/QY01a.png - Oct 30th 2012, 09:51 AMWilmerRe: Need help with an equation!
A start to both:

(m + 1) / 2 = (5m - 10) / 6

3(2x + 1) = 5(x - 1)

If you're unable to continue, you need classroom help... - Oct 30th 2012, 10:02 AMValkyrielRe: Need help with an equation!
I still don't get it...

- Oct 30th 2012, 11:04 AMValkyrielRe: Need help with an equation!
- Oct 30th 2012, 11:06 AMPetrusRe: Need help with an equation!
Hey thats not nice to say!

ehmm u can look step by step soulotion if u dont understand :P

1/2m + 1 = 5/6m -2 - Wolfram|Alpha

3/(x-1) = 5/(2x+1) - Wolfram|Alpha

i think u need to register to see it but its worth it :) hope it help!:) - Oct 30th 2012, 11:45 AMalane1994Re: Need help with an equation!
I assume that you are solving for "m"?

Original Problem:

$\displaystyle \frac{1}{2}m+1=\frac{5}{6}m-2$

Multiply and get and get common denominator.

$\displaystyle \frac{m+2}{2}=\frac{5m+12}{6}$

Can you continue from here?

Also if you use wolfram, be sure to use parentheses.

First one on wolfram

(1/2)m + 1 = (5/6)m -2 - Wolfram|Alpha - Oct 30th 2012, 12:01 PMPetrusRe: Need help with an equation!
sorry i did confuse with x and m

this maybe against the forum rule but ima show u step by step how to solve one of them ( the x one)

u got

3/(x-1)=5/(2x+1)

with a law u can swap idk the name so u got

3(2x+1)=5(x-1)

now lets multiplice the parentes so we got

6x+3=5x-5

now we subtra with 5 (u take -5 on both side) and we got

x+3=-5

u want x alone so u have to get away with 3 so we do -3 both side then u got

x=-8

Now u have solved this problem!:) cheer =D hope u did understand and gl on the other problem :) - Oct 30th 2012, 12:04 PMValkyrielRe: Need help with an equation!
Thanks to both of you :)

- Oct 30th 2012, 12:31 PMWilmerRe: Need help with an equation!
- Oct 30th 2012, 12:35 PMPetrusRe: Need help with an equation!
- Oct 30th 2012, 03:43 PMWilmerRe: Need help with an equation!
My only point is we're not here to do homework...

- Oct 31st 2012, 04:13 AMPetrusRe: Need help with an equation!
- Oct 31st 2012, 06:31 AMalane1994Re: Need help with an equation!
Homework is a big deal. It is worth 30% on my grade in calculus. Try again. And we are not here to do others homework, but rather help.