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Math Help - Probably an easy one for you guys but help needed :-)

  1. #1
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    Dundee
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    Probably an easy one for you guys but help needed :-)

    Background, i have started doing an HNC in Mech Eng through work. It was my choice so i have the motivation to plug away at it.

    I have had a gap in my life of 16 years of doing no maths at all. I was never that great at it in the first place but i have worked extremely hard this year to get it up to a decent standard but i do notice there are gaps in my knowledge.

    So to my problem, i am working out an equation i do not know why a certain steps works the way it does.

    it is as follows = working out for t.

    e^-ct=1-(p/p0) The next step is the problem. It becomes -ct log e = log (p0-p/p0)

    Why does transforming the right side give me what it does? Its not the log part, that's easy its the 1- part.

    Thanks guys
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: Probably an easy one for you guys but help needed :-)

    It's just getting a common denominator:

    1-\frac{p}{p_0}=\frac{p_0}{p_0}-\frac{p}{p_0}=\frac{p_0-p}{p_0}
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  3. #3
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    Re: Probably an easy one for you guys but help needed :-)

    ok, makes sense :-) Thanks
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  4. #4
    MHF Contributor MarkFL's Avatar
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    Re: Probably an easy one for you guys but help needed :-)

    Glad to help, and welcome to the forum!
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