Determine the number of 6-digit numbers that do not have the consequence 17th For example 4713.1572 allowed 5-digit numbers but 1723,3175,0254 are not allowed.

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- Oct 28th 2012, 01:53 PMPetrusword problem
Determine the number of 6-digit numbers that do not have the consequence 17th For example 4713.1572 allowed 5-digit numbers but 1723,3175,0254 are not allowed.

- Oct 28th 2012, 07:25 PMchiroRe: word problem
Hey Petrus.

Consider one digit at a time. If you get a 1 then you have to make sure the next number is not a 7. So if you have 6 digits then you need to check each digit individually with six layers of branches.

First digit is > 1 then go to the next digit. If 1 you can only have 8 possibilities for the next digit instead of 9. You will also have to decide whether you can start with a 0 or not.

Each branch has two choices to consider: you either got a 1 before and need to check for a 7 or you didn't get a 1 and just pick any number. There are 2^5 choices or 32 choices to consider as a tree diagram but you can derive a formula to calculate this (leave the first out because you can always choose a number for first digit).

You should probably show us what you have tried, but if you use a tree diagram you will get 32 different combinations and then you add up the ones where you don't get a 17 in them (you will add up 16 different set of combinations to get the answer). - Oct 28th 2012, 11:07 PMPetrusRe: word problem
I did basicly try but did not went well... Can u show me on another example

- Oct 28th 2012, 11:57 PMchiroRe: word problem
Show us what you have tried and we can work through it.

- Oct 30th 2012, 12:04 PMPetrusRe: word problem
i cant solve this and its on my homework plz some1 can u show me how to solve this!:)

- Oct 30th 2012, 04:30 PMchiroRe: word problem
What I will ask you to do is to outline what you are covering in class: I think this is going to be easier than if I make an attempt on my own since it might be even more confusing.

The tree-approach method above is the best general way to go from a visual tree to a numerical answer (for both combinations of things and probabilities), but you are either not getting it or can't make use of it for reasons I don't know.