# Thread: can somebody help with this problem tomorrow i got test :S

1. ## can somebody help with this problem tomorrow i got test :S

8x5-3x4+7x3-2x2+2x-1 the "x" is -1/2 as fraction

2. ## Re: can somebody help with this problem tomorrow i got test :S

Given:

$f(x)=8x^5-3x^4+7x^3-2x^2+2x-1$

I take it you are to find:

$f\left(-\frac{1}{2} \right)=8\left(-\frac{1}{2} \right)^5-3\left(-\frac{1}{2} \right)^4+7\left(-\frac{1}{2} \right)^3-2\left(-\frac{1}{2} \right)^2+2\left(-\frac{1}{2} \right)-1=$

$-\frac{8}{32}-\frac{3}{16}-\frac{7}{8}-\frac{2}{4}-\frac{2}{2}-1=$

Can you finish?

3. ## Re: can somebody help with this problem tomorrow i got test :S

Its 112/32 or ?

4. ## Re: can somebody help with this problem tomorrow i got test :S

Hello hope u can read my style ^^

ehmm i did write it kinda not good but the step when u get all the bottom to 32 u can also write it as
(-8-6-28-16-32-32)/32

HOPE IT HELP