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Math Help - Words problem nr2

  1. #1
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    Words problem nr2

    361 students at a university has taken a course in the analysis, 223 have taken a course in discrete mathematics, and 188 have read both courses. How many students at the university have taken a course in either analysis or discrete mathematics?
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  2. #2
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    Re: Words problem nr2

    Call all the people in analysis group A and all those in discrete are group B
    The number of people in A and B is AUB
    The number of people not in both is A + B - AUB = 361 + 223 - 188= 396
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  3. #3
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    Re: Words problem nr2

    thats so logic just ohh well dont know why i thought like u :s
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  4. #4
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    Re: Words problem nr2

    Hello, Petrus!

    There is just barely enough information.


    361 students at a university has taken a course in Analysis,
    223 have taken a course in Discrete Mathematics,
    and 188 have taken both courses.
    How many students at the university have taken a course in either Analysis or Discrete Mathematics?

    We can use this formula:

    . . n(A\,\vee\,D) \,=\,n(A) + n(D) - n(A\,\wedge\,D)




    Or we can place the information into a chart . . .

    . . \begin{array}{c|c|c|c|} & \text{Discrete} & \sim\text{Discr.} & \text{Total} \\ \hline \text{Analysis} & 188 && 361 \\ \hline \sim\text{Analy.} & & & \\ \hline \text{Total} & 223 & & \\ \hline \end{array}


    And we can fill in more data . . .

    . . \begin{array}{c|c|c|c|} & \text{Discrete} & \sim\text{Discr.} & \text{Total} \\ \hline \text{Analysis} & 188 & 173 & 361 \\ \hline \sim\text{Analy.}& 35 & & \\ \hline \text{Total} & 223 & & \\ \hline \end{array}


    Therefore: . n(A \vee D) \:=\:188 + 173 + 35 \:=\:396
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