Hello, wolflessalex!
We have a quadratic: .
Let
Substitute: .
Factor: .
And we have: .
Back-substitute:
. .
. .
Hi, i need some help solving the following equation, for some reason i can't get my head around it:
4(2^2x)+31(2^x)-8=0
it would really help me if you can post an explantion on how you solved it from the begining to the end.