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You can now solve this using the Quadratic Formula.
Can you do quadratic aswell - I havent done any with e^{2}
Originally Posted by skaters Can you do quadratic aswell - I havent done any with e^{2} Yes I can, but I won't. It works exactly the same way, your c value just happens to be .
Hello, skaters! I assume that those logs are all base-ten. We must discard the negative root. Therefore: .
Thanks !
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