Results 1 to 3 of 3

Math Help - Helpppp!!!!!!!

  1. #1
    Newbie
    Joined
    Oct 2007
    Posts
    2

    Exclamation Helpppp!!!!!!!

    Solve For b: ax(squared) + bx+c=y.

    Three times the larger of 2 consecutive even intergers, decreased by the smaller is 58. Find the numbers.

    Find 3 consecutive intergers such that the sum of the first two is 74 more than the third.

    A pipe is 48 inches long. David wants to cut the pipe into three pieces so that the second piece is 1 inch less than the length of the third. The first piece is 5 times as long as the third. How long is each piece?

    Ron runs a ski train. One day he noticed that the train contained 13 more women than men *including himself*. If there were a total of 165 people on the train, how many of them were men?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by amy07 View Post
    Solve For b: ax(squared) + bx+c=y.
    this means that we want to get b on one side of the equation by itself. so get rid of everything on the same side with b.


    ax^2 + bx + c = y .......subtract ax^2 + c from both sides

    \Rightarrow bx = y - ax^2 - c .........now if x \ne 0 we can divide by it.

    \Rightarrow b = \frac yx - ax - \frac cx

    Three times the larger of 2 consecutive even intergers, decreased by the smaller is 58. Find the numbers.
    Let n be the smallest even integer.
    Then n + 2 is the next even integer.

    we are told that 3 times (n + 2), subtracting the smaller is 58. thus,

    3(n + 2) - n = 58

    now solve for n so you can find the integers.

    Find 3 consecutive intergers such that the sum of the first two is 74 more than the third.
    Let the first integer be n
    then the next is n + 1
    and the largest is n + 2

    the sum of the first two is 74 + the third. thus,

    n + (n + 1) = 74 + (n + 2)

    now solve for n to find the integers

    A pipe is 48 inches long. David wants to cut the pipe into three pieces so that the second piece is 1 inch less than the length of the third. The first piece is 5 times as long as the third. How long is each piece?
    Let a be the length of the first piece,
    Let b be the length of the second piece,
    Let c be the length of the third piece,

    then we have a + b + c = 48 .................(1)

    since the second piece is 1 inch less than the length of the third, we have:

    b = c - 1

    \Rightarrow b - c = -1 .....................(2)

    since the first piece is 5 times as long as the third, we have:

    a = 5c

    a - 5c = 0 ........................(3)


    thus we obtain the system:

    a + b + c = 48 ......................(1)
    b - c = -1 ............................(2)
    a - 5c = 0 .............................(3)

    now solve this system to get a,b, \mbox{ and } c




    if you do not know how to solve simultaneous equations, you can do this in one variable.

    Let the length of the third be a

    then the length of the second is a - 1

    and the length of the first is 5a

    the pieces add up to 48, so:

    a + (a - 1) + 5a = 48

    now just find a, and then substitute its values into the equation to find the other pieces

    Ron runs a ski train. One day he noticed that the train contained 13 more women than men *including himself*. If there were a total of 165 people on the train, how many of them were men?
    Let's keep this in one variable:

    Let the number of men be m.
    since the train contained 13 more women than men, the number of women is m + 13.

    these must add up to 165 people, thus:

    m + (m + 13) = 165

    now solve for m
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Oct 2007
    Posts
    2

    i dont know where to...

    i dont know where i go to see where people responded =\



    Okay, I found the response. thank you so much for the help!!!!!!!!!!!! i really really appreciate it!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Helpppp!!!!
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: December 2nd 2007, 05:50 PM
  2. [SOLVED] helpppp please. nobody can solve it??
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: October 29th 2007, 06:15 AM
  3. Graphing helpppp...
    Posted in the Pre-Calculus Forum
    Replies: 6
    Last Post: November 17th 2006, 03:54 AM
  4. Graphing helpppp...
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: November 12th 2006, 06:38 AM
  5. helpppp
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: July 15th 2006, 01:28 AM

Search Tags


/mathhelpforum @mathhelpforum