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Math Help - SQRT(x-2)-1 = 0

  1. #1
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    SQRT(x-2)-1 = 0

    Needing some review with solving this

    SQRT(x-2)-1 = 0

    I carried the 1 over making

    SQRT(x-2)= 1

    at this point do I want to carry the 2 over as well?

    or do I square the 1 right away?
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  2. #2
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    Re: SQRT(x-2)-1 = 0

    square both sides ...

    (\sqrt{x - 2})^2 = 1^2

    ... proceed.
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  3. #3
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    Re: SQRT(x-2)-1 = 0

    deleting
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  4. #4
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    Re: SQRT(x-2)-1 = 0

    wait i see my mistake...
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  5. #5
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    Re: SQRT(x-2)-1 = 0

    if the next step is (x-2)(x-2) = 1

    I'm going to be left with

    X^2 -4x + 3 = 0

    This ties back to my other post when im solving f(x) = 0 for 2 < x < 11

    This doesn't seem like it could be solved.

    inless

    i simplify it to (1 + -1x)(3 + -1x) = 0

    X = - 1 or X = -3

    Did i do that right?
    Both wouldnt fit into the interval.
    Last edited by wolfwood; October 16th 2012 at 04:18 PM.
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  6. #6
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    Re: SQRT(x-2)-1 = 0

    (\sqrt{x-2})^2 = x-2 , not (x-2)(x-2)
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  7. #7
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    Re: SQRT(x-2)-1 = 0

    I made that more complicated then it needed to be. thanks.
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