square both sides ...
... proceed.
if the next step is (x-2)(x-2) = 1
I'm going to be left with
X^2 -4x + 3 = 0
This ties back to my other post when im solving f(x) = 0 for 2 < x < 11
This doesn't seem like it could be solved.
inless
i simplify it to (1 + -1x)(3 + -1x) = 0
X = - 1 or X = -3
Did i do that right?
Both wouldnt fit into the interval.