SQRT(x-2)-1 = 0

Needing some review with solving this

SQRT(x-2)-1 = 0

I carried the 1 over making

SQRT(x-2)= 1

at this point do I want to carry the 2 over as well?

or do I square the 1 right away?

square both sides ...

$\displaystyle (\sqrt{x - 2})^2 = 1^2$

... proceed.

deleting

wait i see my mistake...

if the next step is (x-2)(x-2) = 1

I'm going to be left with

X^2 -4x + 3 = 0

This ties back to my other post when im solving f(x) = 0 for 2 < x < 11

This doesn't seem like it could be solved.

inless

i simplify it to (1 + -1x)(3 + -1x) = 0

X = - 1 or X = -3

Did i do that right?
Both wouldnt fit into the interval.

$\displaystyle (\sqrt{x-2})^2 = x-2$ , not $\displaystyle (x-2)(x-2)$

I made that more complicated then it needed to be. thanks.