Hello Iv been told to rearrang the following equation: n^{m+1} = (C^{m+1} x (V - U)^{m+1}) / (Q x D)^{m+1} so that: n^{m+1} x Q x D = ?????? every time iv done it iv been told i got it wrong. Can some one please help me.
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Thanks for the help skeeter. This there a way to get a simalar equation but without the (QD)^m factor?
I get the feeling there is more to this problem than what you've posted. Please state the original problem and the given directions ...
Originally Posted by killick Hello Iv been told to rearrang the following equation: n^{m+1} = (C^{m+1} x (V - U)^{m+1}) / (Q x D)^{m+1} so that: n^{m+1} x Q x D = ?????? every time iv done it iv been told i got it wrong. Can some one please help me. I suspect you really want n x Q x D= rather than the n+1 power of r. From , you can write it as and take the n+1 root to get and then multiply both sides by QD:
Iv got the equation: I = n^(m+1) QD K W X But need to substitute the n^(m+1) QD part using this equation: n^(m+1) = (C^(m+1) x (V - U)^(m+1)) / (Q x D)^(m+1) But with out any QD factors left on the right hand side
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