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Math Help - help to rearrang equation

  1. #1
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    help to rearrang equation

    Hello

    Iv been told to rearrang the following equation:

    nm+1 = (Cm+1 x (V - U)m+1) / (Q x D)m+1

    so that:

    nm+1 x Q x D = ??????

    every time iv done it iv been told i got it wrong.
    Can some one please help me.
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  2. #2
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    Re: help to rearrang equation

    n^{m+1} = \frac{C^{m+1}(V-U)^{m+1}}{(QD)^{m+1}}

    n^{m+1} = \frac{C^{m+1}(V-U)^{m+1}}{(QD)(QD)^m}

    n^{m+1}QD = \frac{C^{m+1}(V-U)^{m+1}}{(QD)^m}
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  3. #3
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    Re: help to rearrang equation

    Thanks for the help skeeter.
    This there a way to get a simalar equation but without the (QD)^m factor?
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  4. #4
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    Re: help to rearrang equation

    I get the feeling there is more to this problem than what you've posted. Please state the original problem and the given directions ...
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  5. #5
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    Re: help to rearrang equation

    Quote Originally Posted by killick View Post
    Hello

    Iv been told to rearrang the following equation:

    nm+1 = (Cm+1 x (V - U)m+1) / (Q x D)m+1

    so that:

    nm+1 x Q x D = ??????

    every time iv done it iv been told i got it wrong.
    Can some one please help me.
    I suspect you really want n x Q x D= rather than the n+1 power of r.

    From n^{m+1}= \frac{C^{m+1}(V- U)^{m+1}}{(QD)^{m+1}}, you can write it as n^{m+1}= \left(\frac{C(V- U)}{QD}\right)^{m+1}
    and take the n+1 root to get n=\frac{C(V- U)}{QD} and then multiply both sides by QD:
    nQD= C(V- U)
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  6. #6
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    Re: help to rearrang equation

    Iv got the equation:

    I = n^(m+1) QD K W X

    But need to substitute the n^(m+1) QD part using this equation:

    n^(m+1) = (C^(m+1) x (V - U)^(m+1)) / (Q x D)^(m+1)

    But with out any QD factors left on the right hand side
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