Hello

Iv been told to rearrang the following equation:

n^{m+1}= (C^{m+1}x (V - U)^{m+1}) / (Q x D)^{m+1}

so that:

n^{m+1}x Q x D = ??????

every time iv done it iv been told i got it wrong.

Can some one please help me.

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- October 14th 2012, 08:03 AMkillickhelp to rearrang equation
Hello

Iv been told to rearrang the following equation:

n^{m+1}= (C^{m+1}x (V - U)^{m+1}) / (Q x D)^{m+1}

so that:

n^{m+1}x Q x D = ??????

every time iv done it iv been told i got it wrong.

Can some one please help me. - October 14th 2012, 09:06 AMskeeterRe: help to rearrang equation

- October 14th 2012, 10:22 AMkillickRe: help to rearrang equation
Thanks for the help skeeter.

This there a way to get a simalar equation but without the (QD)^m factor? - October 14th 2012, 12:21 PMskeeterRe: help to rearrang equation
I get the feeling there is more to this problem than what you've posted. Please state the original problem and the given directions ...

- October 14th 2012, 01:48 PMHallsofIvyRe: help to rearrang equation
- October 17th 2012, 05:47 AMkillickRe: help to rearrang equation
Iv got the equation:

I = n^(m+1) QD K W X

But need to substitute the n^(m+1) QD part using this equation:

n^(m+1) = (C^(m+1) x (V - U)^(m+1)) / (Q x D)^(m+1)

But with out any QD factors left on the right hand side