3ab + 5/2b. The book I have states the answer is 6ab^2 + 5/2b. How was the "6" derived? Is it simply 3ab * 2b that brings about 6ab^2?

Thanks!

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- Oct 11th 2012, 06:35 AMMathClownSimplification of Expression
3ab + 5/2b. The book I have states the answer is 6ab^2 + 5/2b. How was the "6" derived? Is it simply 3ab * 2b that brings about 6ab^2?

Thanks! - Oct 11th 2012, 06:41 AMmrmaaza123Re: Simplification of Expression
Take the LCM of 3ab and 5/2b like in regular addition of fractions. So for that you will have to multiply 3ab with 2b which will give you 6ab^2.

- Oct 11th 2012, 06:45 AMMathClownRe: Simplification of Expression
Do you use the lowest common denominator for 3ab since it's not a fraction? What are you saying? Simply multiply 3ab by 2b?

- Oct 11th 2012, 07:08 AMmrmaaza123Re: Simplification of Expression
Well what i meant is, that since you are not given the denominator for 3ab you can assume that it is a fraction with denominator 1, so that the lcm(1,2b)=2b.

Then you can simply multiply 3ab by 2b and 1 by 2b to get a common denominator for 3ab and 5 that is 2b.

So the answer will turn out to be (6ab^2 +5)/2b. - Oct 11th 2012, 11:22 AMalane1994Re: Simplification of Expression
$\displaystyle 3ab+\frac{5}{2b}$

$\displaystyle (\frac{3ab}{1}\times\frac{2b}{2b})+\frac{5}{2b}$

$\displaystyle \frac{6ab^2}{2b}+\frac{5}{2b}$

$\displaystyle \frac{6ab^2+5}{2b}$

I believe that this is correct, but I could be wrong. Someone check my math and verify that it is correct. I don't want to give them the incorrect process. I cannot remember if you can get rid of the b on the bottom or not...(Thinking)