solving equation

The graphs with equations http://mapleta7.eps.surrey.ac.uk:808...kipaopgngm.gif and http://mapleta7.eps.surrey.ac.uk:808...plafpdjmch.gif meet at two points. At one of these points, http://mapleta7.eps.surrey.ac.uk:808...jijlbkpdha.gif. What is the value of http://mapleta7.eps.surrey.ac.uk:808...gmiemniapm.gif at the other point?

I dont know how to do this question, I think i should set them equal to each other,

any help appreciated.

I recommend substituting for y as given by the first equation into the second equation. This will given you a quadratic in x. Solve this, then plug the root not equal to 2 into the first equation for x to determine the value of y at the other point.

Quote:

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Originally Posted by MarkFL2

I recommend substituting for y as given by the first equation into the second equation. This will given you a quadratic in x. Solve this, then plug the root not equal to 2 into the first equation for x to determine the value of y at the other point.

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Am a bit confused, i did what you said



9x^{2} -20 = 0 [/tex]




and got

so i plug this answer into the first equation to get an answer for y ?

If you substitute for y using the first equation, into the second equation, you get:



Distribute the x on the left side:



Multiply through by 4:



Write quadratic in standard form:



Now factor to find the roots.