what is the first step to do this??

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- Oct 7th 2012, 04:32 PMdanielssimplify 15/x^4 +2/x^2+2x+2
what is the first step to do this??

- Oct 7th 2012, 05:20 PMskeeterRe: simplify 15/x^4 +2/x^2+2x+2
$\displaystyle \frac{15}{x^4} + \frac{2}{x^2} + 2x + 2$

common denominator is $\displaystyle x^4$ ... - Oct 7th 2012, 06:56 PMSoroban
Hello, daniels!

Don't write the problem in the subject line.

Quote:

What is the first step to do this??

Doesn't this look silly?

Your problem could be:

. . $\displaystyle \begin{array}{c} \dfrac{15}{x^4} + \dfrac{2}{x^2} + 2x + 2 \\ \\ \dfrac{15}{x^4} + \dfrac{2}{x^2+2x} + 2 \\ \\ \dfrac{15}{x^4} + \dfrac{2}{x^2+2x+2} \\ \\ \dfrac{15}{x^4 + \dfrac{2}{x^2}} + 2x + 2 \\ \\ \dfrac{15}{x^4 + \dfrac{2}{x^2+2x}} + 2 \\ \\ \dfrac{15}{x^4+\dfrac{2}{x^2+2x+2}} \end{array}$

But I bet it is: .$\displaystyle \frac{15}{x^4} + \frac{2}{x^2+2x+2}$

First step: get a common denominator.