$\displaystyle (2x+1)/(x^2+4x+4) - (6x)/(x^2-4) + 3/(x-2)$ Please help explain how to solve this? Thanks!
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$\displaystyle \frac{2x+1}{(x+2)^2} - \frac{6x}{(x-2)(x+2)} + \frac{3}{x-2}$ you need a common denominator ... $\displaystyle (x+2)^2(x-2)$
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