Help me factor a polynomial from graph thepry

Yeah that's correct.

Quote:

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Originally Posted by Wilmer

1^(anything) = 1
So x^n * 1^n = x^n

RULE: a^n * b^n = (ab)^n

ALSO: (-1)^2n = 1 ; (-1)^(2n+1) = -1 ; where n is any integer

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oh, my mistake,