Results 1 to 3 of 3
Like Tree1Thanks
  • 1 Post By Soroban

Math Help - Unable to simplify equation

  1. #1
    Newbie
    Joined
    Jul 2012
    From
    Texas
    Posts
    7

    Question Unable to simplify equation

    I have the function f(n) = n2 + (n2 - (n-1)) + (n2 - 2(n-1)) + (n2 - 3(n-1))

    I tried pulling an "n-1" out like so:
    f(n) = n2 + (n-1) [ (n2-1) + (n2-2) + (n2-3) ]

    But when I run test cases on it against the original, it doesn't come out right.
    I'm pretty positive I can't take an "n^2" out to simplify it.

    Is that the simplest I can express that equation?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,737
    Thanks
    643

    Re: Unable to simplify equation

    Hello, jonarmani!

    I have the function f(n) \:=\:n^2+ \big[n^2 - (n-1)\big] + \big[n^2 - 2(n-1)\big] + \big[n^2 - 3(n-1)\big]

    I tried pulling an "n-1" out like so:
    f(n) \:=\: n^2 + (n-1) \big[(n^2-1) + (n^2-2) + (n^2-3)\big] . Illegal!

    But when I run test cases on it against the original, it doesn't come out right.
    I'm pretty positive I can't take an "n^2" out to simplify it.

    Is that the simplest I can express that equation?

    Why not add the four polynomials?

    n^2 + (n^2 - n + 1) + (n^2 - 2n + 2) + (n^2 - 3n +3)

    . . . . . . . . =\;\;4n^2 - 6n + 6 \;\;=\;\;2(2n^2 - 3n + 3)
    Thanks from jonarmani
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jul 2012
    From
    Texas
    Posts
    7

    Re: Unable to simplify equation

    Thank you!!!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. unable to understand cosets
    Posted in the Advanced Algebra Forum
    Replies: 4
    Last Post: November 22nd 2009, 08:23 PM
  2. Unable to get a step in the problem :(
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: April 21st 2009, 12:15 AM
  3. Unable to simplify an expression
    Posted in the Trigonometry Forum
    Replies: 6
    Last Post: January 27th 2008, 01:39 PM

Search Tags


/mathhelpforum @mathhelpforum