I have the function f(n) = n2 + (n2 - (n-1)) + (n2 - 2(n-1)) + (n2 - 3(n-1))
I tried pulling an "n-1" out like so:
f(n) = n2 + (n-1) [ (n2-1) + (n2-2) + (n2-3) ]
But when I run test cases on it against the original, it doesn't come out right.
I'm pretty positive I can't take an "n^2" out to simplify it.
Is that the simplest I can express that equation?