I have this equation here that needs graphing but it has two restriction. Does that mean it will have two asymptotes? Any help is appreciated, you dont need to draw the graph just tell me how to do it!
The equation is
which eaquals with restriction of x cannot be -4 and -2
Your function to graph is .
What I see is:
1/x (I know what that its graph looks like),
then shifted horizontally left 2 units (now it's 1/(x+2)),
then stretched veritcally by a factor of 7 (now it's 7/(x+2)),
then reflected about the x-axis (now it's - 7/(x+2)),
then shifted up vertically 1 unit (now it's 1 - 7/(x+2)).
Oh yeah, and then I have to pull x=-4 out of the domain.
I hope that helps you graph it.
Hello, sakonpure6!
I have this equation here that needs graphing but it has two restrictions.
Does that mean it will have two asymptotes?
The equation is: . . . . . which equals: . . This is wrong!
. . with restriction of x cannot be -4 and -2. .
We have: .
We are expected to know the graph of
This graph is translated 2 units to the left and 1 unit up.