Hi; solve logbase6 36^5x. 6^2 = 36^5x 2 =5x therefore x=2/5. Is that correct.I think it is
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Or do both sides need to have same base therefore 6^2 = (6^2)^5x giving 6^2 = 6^10x resulting in 2 = 10x therefore x = 2/10 Yeah that looks better.
Presumably, the equation is: Converting from logarithmic to exponential form is one way we could proceed, but here is another: We may use the log property to write: Using the above property again, we have: Since we now have:
Great thank you just needed to make sure.
Another way: Hence:
another way 6^2= (6^2)^5x 36 = 36^5x 5x=1
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