Hi;

solve logbase6 36^5x.

6^2 = 36^5x

2 =5x therefore x=2/5.

Is that correct.I think it is

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- Sep 27th 2012, 10:18 AManthonyelogarithm problem
Hi;

solve logbase6 36^5x.

6^2 = 36^5x

2 =5x therefore x=2/5.

Is that correct.I think it is - Sep 27th 2012, 10:23 AManthonyeRe: logarithm problem
Or do both sides need to have same base therefore

6^2 = (6^2)^5x

giving 6^2 = 6^10x

resulting in 2 = 10x therefore x = 2/10

Yeah that looks better. - Sep 27th 2012, 12:00 PMMarkFLRe: logarithm problem
Presumably, the equation is:

Converting from logarithmic to exponential form is one way we could proceed, but here is another:

We may use the log property to write:

Using the above property again, we have:

Since we now have:

- Sep 27th 2012, 12:03 PManthonyeRe: logarithm problem
Great thank you just needed to make sure.

- Sep 27th 2012, 12:09 PMMarkFLRe: logarithm problem
Another way:

Hence:

- Sep 27th 2012, 03:37 PMbjhopperRe: logarithm problem
another way

6^2= (6^2)^5x

36 = 36^5x

5x=1