# Thread: What do I need to do with this equation?

1. ## What do I need to do with this equation?

20x -10 = 6+12x

Maths was never my best subject!

Thanks!

2. ## Re: What do I need to do with this equation?

20x -10 = 6+12x

You have to solve for x, so you need to isolate x, to do that, you can subtract 12x from both sides: $20x-10-12x =6+12x-12x$ and you will get -> $8x-10=6$, now add 10 to both sides and you get rid of that -10 on the left side and you will have -> $8x=6+10=16$, now you have 8x=16, you can divide both sides by 8 to get rid of that 8 next to x and you will get -> $x=\frac{16}{8}$ -> $x=2$.

3. ## Re: What do I need to do with this equation?

Originally Posted by Sb2011
20x -10 = 6+12x
add 10 and subtract 12x from both sides ...

4. ## Re: What do I need to do with this equation?

I don't know why I didn't see it! More practice is needed I suppose. Thanks again guys!