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  1. #1
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    help polynomial

    given that (x^2-2x+3)(x^2+Kx-2) = x^4-15x^3+qx^2+px-6
    find the values of K, p and q

    iv tried n jst keep gettin lost
    thx
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  2. #2
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    Quote Originally Posted by kls7162 View Post
    given that (x^2-2x+3)(x^2+Kx-2) = x^4-15x^3+qx^2+px-6
    find the values of K, p and q

    iv tried n jst keep gettin lost
    thx
    Hello,

    1. expand the brackets at the LHS of your equation.
    2. collect like terms

    You'll get:

    (x^2-2x+3)(x^2+Kx-2) =  x^4+x^3(k-2)+x^2(1-2k)+x(3k+4)-6

    Now compare this result with the coefficients at the RHS of the given equation:

    \begin{array}{l}k-2=-15\\1-2k=q \\ 3k+4=p\end{array} This is a system of 3 linear equations which could be solved for k, p, q.

    (For confirmation only: I've got k = -13, q = 27, p = -35) but you'd better check my calculations!
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