1. ## Word Problem Issue

I'm having serious problems solving this problem....

A golden rectangle is a rectagle whoes length is approximately 1.6 times the width. The early Greeks thought that a rectangle with these dimensions was the most pleasing to the eye and examples of the golden rectangle are found in many early works of art. For exampls, the Parthenon in Athens contains many examples of golden rectangles. Mike Hallaham would like to plant a rectangle garden in the shape of a golden rectagnle. If he has 78 feet of fencing available, find the dimensions of the garden.

what is the width of the garden and the length?

2. ## Re: Word Problem Issue

Let l be the length of the fence and w be the width. you know that lenth is approximately 1.6 times width, so you have your first equation: $l=1.6w$. Since there's 78 feet of fence available, and fence is a rectangle, which means that it has 4 sides (2 length and 2 width), $2l+2w=78$, now you have your second equation which means you'll be able to solve for both variables by method of substitution or addition and after solving it for l and w, you will have the dimensions of the fence.

3. ## Re: Word Problem Issue

when trying to solve I got w=−(1-39) and l=1 which is wrong

4. ## Re: Word Problem Issue

Originally Posted by marukai47
when trying to solve I got w=−(1-39) and l=1 which is wrong
How did you get that results?

$l=1.6w$, substitute that in the second equation $2l+2w=78$ and you will get $2(1.6w)+2w=78$ -> $3.2w+2w=78$ -> $5.2w=78$ -> $w=\frac{78}{5.2}$ -> $w=15$. Since $l=1.6w$, $l=1.6*15=24$.

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### If the with of a rectangle is 23 and the lenth is 53 what is the area of the rectangle?

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