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Math Help - BEDMAS Question.

  1. #1
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    BEDMAS Question.

    The answer for this question is 51 but I can't seem to get it.

    4^3-5[(28-4)/2^3]+√100/25

    Any help would be greatly appreciated!
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  2. #2
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    Re: BEDMAS Question.

    Quote Originally Posted by mac217 View Post
    The answer for this question is 51 but I can't seem to get it.

    4^3-5[(28-4)/2^3]+√100/25

    Any help would be greatly appreciated!
    Would you show us what you did please?
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  3. #3
    MHF Contributor MarkFL's Avatar
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    Re: BEDMAS Question.

    We are given to evaluate:

    4^3-5\left(\frac{28-4}{2^3} \right)+\sqrt{\frac{100}{25}}

    Where do you think we should begin first?
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  4. #4
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    Re: BEDMAS Question.

    Here are my steps,

    =4^3-5[24/2^3]+√100/25
    =4^3-5x3+√100/25
    =64-5x3+√100/25
    =64-5x3+4
    =64-15+4
    =64-19
    =45
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  5. #5
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    Re: BEDMAS Question.

    The brackets.
    28-4=24
    2^3=8
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  6. #6
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    Re: BEDMAS Question.

    Hello mac217.
    4^3-5(\frac{28-4}{2^3})+\sqrt{\frac{100}{25}}=64-5(\frac{24}{8})+\sqrt{4}=64-5*3+2=64-15+2=51. I hope this helps.
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  7. #7
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    Re: BEDMAS Question.

    Thank you so much Diogyk!
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  8. #8
    MHF Contributor MarkFL's Avatar
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    Re: BEDMAS Question.

    Quote Originally Posted by DIOGYK View Post
    Hello mac217.
    4^3-5(\frac{28-4}{2^3})+\sqrt{\frac{100}{25}}=64-5(\frac{24}{8})+\sqrt{4}=64-5*3+2=64-15+2=51. I hope this helps.
    Why do you come along after others are already trying to engage a poster and give a full solution?

    When I made my first post here, I did not see another had already posted because we posted at the same time, but because the other poster was first, I would then let them continue to engage the OP.
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  9. #9
    Junior Member DIOGYK's Avatar
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    Re: BEDMAS Question.

    Quote Originally Posted by MarkFL2 View Post
    Why do you come along after others are already trying to engage a poster and give a full solution?

    When I made my first post here, I did not see another had already posted because we posted at the same time, but because the other poster was first, I would then let them continue to engage the OP.
    I agree I was little rude to the original posters, you and Prove It, by posting the full solution, sorry, I will think more next time before I post after other's who are already helping. : )
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  10. #10
    MHF Contributor MarkFL's Avatar
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    Re: BEDMAS Question.

    Thank you for your consideration and maturity.
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