# BEDMAS Question.

• Sep 18th 2012, 07:58 PM
mac217
BEDMAS Question.
The answer for this question is 51 but I can't seem to get it.

4^3-5[(28-4)/2^3]+√100/25

Any help would be greatly appreciated!
• Sep 18th 2012, 08:05 PM
Prove It
Re: BEDMAS Question.
Quote:

Originally Posted by mac217
The answer for this question is 51 but I can't seem to get it.

4^3-5[(28-4)/2^3]+√100/25

Any help would be greatly appreciated!

Would you show us what you did please?
• Sep 18th 2012, 08:05 PM
MarkFL
Re: BEDMAS Question.
We are given to evaluate:

$4^3-5\left(\frac{28-4}{2^3} \right)+\sqrt{\frac{100}{25}}$

Where do you think we should begin first?
• Sep 18th 2012, 08:07 PM
mac217
Re: BEDMAS Question.
Here are my steps,

=4^3-5[24/2^3]+√100/25
=4^3-5x3+√100/25
=64-5x3+√100/25
=64-5x3+4
=64-15+4
=64-19
=45
• Sep 18th 2012, 08:11 PM
mac217
Re: BEDMAS Question.
The brackets.
28-4=24
2^3=8
• Sep 18th 2012, 08:11 PM
DIOGYK
Re: BEDMAS Question.
Hello mac217.
$4^3-5(\frac{28-4}{2^3})+\sqrt{\frac{100}{25}}=64-5(\frac{24}{8})+\sqrt{4}=64-5*3+2=64-15+2=51$. I hope this helps.
• Sep 18th 2012, 08:12 PM
mac217
Re: BEDMAS Question.
Thank you so much Diogyk!
• Sep 18th 2012, 08:18 PM
MarkFL
Re: BEDMAS Question.
Quote:

Originally Posted by DIOGYK
Hello mac217.
$4^3-5(\frac{28-4}{2^3})+\sqrt{\frac{100}{25}}=64-5(\frac{24}{8})+\sqrt{4}=64-5*3+2=64-15+2=51$. I hope this helps.

Why do you come along after others are already trying to engage a poster and give a full solution?

When I made my first post here, I did not see another had already posted because we posted at the same time, but because the other poster was first, I would then let them continue to engage the OP.
• Sep 18th 2012, 08:35 PM
DIOGYK
Re: BEDMAS Question.
Quote:

Originally Posted by MarkFL2
Why do you come along after others are already trying to engage a poster and give a full solution?

When I made my first post here, I did not see another had already posted because we posted at the same time, but because the other poster was first, I would then let them continue to engage the OP.

I agree I was little rude to the original posters, you and Prove It, by posting the full solution, sorry, I will think more next time before I post after other's who are already helping. : )
• Sep 18th 2012, 08:40 PM
MarkFL
Re: BEDMAS Question.
Thank you for your consideration and maturity. (Cool)