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Math Help - help again :S

  1. #1
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    help again :S

    this one i got no ide what to do =S, i dont get it how i should do:
    soulve the ekvation The solution should be of the form a+bi
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  2. #2
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    Re: help again :S

    Quote Originally Posted by Petrus View Post
    this one i got no ide what to do =S, i dont get it how i should do:
    soulve the ekvation The solution should be of the form a+bi
    -13\text{Re}(z)=2~\&~15\text{Im}(z)=9
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  3. #3
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    Re: help again :S

    ehmm i dont get it...
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  4. #4
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    Re: help again :S

    Quote Originally Posted by Petrus View Post
    ehmm i dont get it...
    Well the real part of the expression oh the left must equal the real part of the expression on the right.
    Same idea for the imaginary parts.
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  5. #5
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    Re: help again :S

    how can i see the re and im on z?
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    Re: help again :S

    Quote Originally Posted by Petrus View Post
    how can i see the re and im on z?
    If z=a+bi then \text{Re}(z)=a~\&~\text{Im}(z)=b

    \text{Re}(2+9i)=2~\&~\text{Im}(2+9i)=9

    \text{Re}(z-14\overline{z})=-13a~\&~\text{Im}(z-14\overline{z})=15b
    Last edited by Plato; September 18th 2012 at 09:51 AM.
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  7. #7
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    Re: help again :S

    a = -2/13 is correct
    b = 9/15 is wrong ( acording to the computer program) what do i do wrong?
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  8. #8
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    Re: help again :S

    Try reducing 9/15...
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  9. #9
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    Re: help again :S

    heheh ty ur best
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