# help again :S

• Sep 18th 2012, 08:10 AM
Petrus
help again :S
this one i got no ide what to do =S, i dont get it how i should do:
soulve the ekvation https://webwork.math.su.se/webwork2_...4caa0c5f21.pngThe solution should be of the form a+bi
• Sep 18th 2012, 08:19 AM
Plato
Re: help again :S
Quote:

Originally Posted by Petrus
this one i got no ide what to do =S, i dont get it how i should do:
soulve the ekvation https://webwork.math.su.se/webwork2_...4caa0c5f21.pngThe solution should be of the form a+bi

$-13\text{Re}(z)=2~\&~15\text{Im}(z)=9$
• Sep 18th 2012, 08:45 AM
Petrus
Re: help again :S
ehmm i dont get it...
• Sep 18th 2012, 08:54 AM
Plato
Re: help again :S
Quote:

Originally Posted by Petrus
ehmm i dont get it...

Well the real part of the expression oh the left must equal the real part of the expression on the right.
Same idea for the imaginary parts.
• Sep 18th 2012, 09:04 AM
Petrus
Re: help again :S
how can i see the re and im on z?
• Sep 18th 2012, 09:14 AM
Plato
Re: help again :S
Quote:

Originally Posted by Petrus
how can i see the re and im on z?

If $z=a+bi$ then $\text{Re}(z)=a~\&~\text{Im}(z)=b$

$\text{Re}(2+9i)=2~\&~\text{Im}(2+9i)=9$

$\text{Re}(z-14\overline{z})=-13a~\&~\text{Im}(z-14\overline{z})=15b$
• Sep 18th 2012, 09:24 AM
Petrus
Re: help again :S
a = -2/13 is correct
b = 9/15 is wrong ( acording to the computer program) what do i do wrong?
• Sep 18th 2012, 09:49 AM
MarkFL
Re: help again :S
Try reducing 9/15...
• Sep 18th 2012, 09:52 AM
Petrus
Re: help again :S
heheh ty ur best :D